-2(3y-7)+2y=8+2(7y-3)

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Solution for -2(3y-7)+2y=8+2(7y-3) equation: 



-2(3y-7)+2y=8+2(7y-3)

We move all terms to the left:

-2(3y-7)+2y-(8+2(7y-3))=0

We add all the numbers together, and all the variables

2y-2(3y-7)-(8+2(7y-3))=0

We multiply parentheses

2y-6y-(8+2(7y-3))+14=0



We calculate terms in parentheses: -(8+2(7y-3)), so:

8+2(7y-3)

determiningTheFunctionDomain
2(7y-3)+8

We multiply parentheses

14y-6+8

We add all the numbers together, and all the variables

14y+2

Back to the equation:

-(14y+2)



We add all the numbers together, and all the variables

-4y-(14y+2)+14=0

We get rid of parentheses

-4y-14y-2+14=0

We add all the numbers together, and all the variables

-18y+12=0

We move all terms containing y to the left, all other terms to the right

-18y=-12

y=-12/-18

y=2/3

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