-2(3y-8)+4y=6+2(7y-1)

Solution for -2(3y-8)+4y=6+2(7y-1) equation:

-2(3y-8)+4y=6+2(7y-1)

We move all terms to the left:

-2(3y-8)+4y-(6+2(7y-1))=0

We add all the numbers together, and all the variables

4y-2(3y-8)-(6+2(7y-1))=0

We multiply parentheses

4y-6y-(6+2(7y-1))+16=0


We calculate terms in parentheses: -(6+2(7y-1)), so:

6+2(7y-1)

determiningTheFunctionDomain
2(7y-1)+6

We multiply parentheses

14y-2+6

We add all the numbers together, and all the variables

14y+4

Back to the equation:

-(14y+4)


We add all the numbers together, and all the variables

-2y-(14y+4)+16=0

We get rid of parentheses

-2y-14y-4+16=0

We add all the numbers together, and all the variables

-16y+12=0

We move all terms containing y to the left, all other terms to the right

-16y=-12

y=-12/-16

y=3/4