-2(3y-8)-y=-3(y-2)

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Solution for -2(3y-8)-y=-3(y-2) equation: 



-2(3y-8)-y=-3(y-2)

We move all terms to the left:

-2(3y-8)-y-(-3(y-2))=0

We add all the numbers together, and all the variables

-1y-2(3y-8)-(-3(y-2))=0

We multiply parentheses

-1y-6y-(-3(y-2))+16=0



We calculate terms in parentheses: -(-3(y-2)), so:

-3(y-2)

We multiply parentheses

-3y+6

Back to the equation:

-(-3y+6)



We add all the numbers together, and all the variables

-7y-(-3y+6)+16=0

We get rid of parentheses

-7y+3y-6+16=0

We add all the numbers together, and all the variables

-4y+10=0

We move all terms containing y to the left, all other terms to the right

-4y=-10

y=-10/-4

y=2+1/2

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