-2(3y-9)-y=-2(y-2)

Solution for -2(3y-9)-y=-2(y-2) equation:

-2(3y-9)-y=-2(y-2)

We move all terms to the left:

-2(3y-9)-y-(-2(y-2))=0

We add all the numbers together, and all the variables

-1y-2(3y-9)-(-2(y-2))=0

We multiply parentheses

-1y-6y-(-2(y-2))+18=0


We calculate terms in parentheses: -(-2(y-2)), so:

-2(y-2)

We multiply parentheses

-2y+4

Back to the equation:

-(-2y+4)


We add all the numbers together, and all the variables

-7y-(-2y+4)+18=0

We get rid of parentheses

-7y+2y-4+18=0

We add all the numbers together, and all the variables

-5y+14=0

We move all terms containing y to the left, all other terms to the right

-5y=-14

y=-14/-5

y=2+4/5