-2(3y-9)-y=-4(y-4)

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Solution for -2(3y-9)-y=-4(y-4) equation:



-2(3y-9)-y=-4(y-4)
We move all terms to the left:
-2(3y-9)-y-(-4(y-4))=0
We add all the numbers together, and all the variables
-1y-2(3y-9)-(-4(y-4))=0
We multiply parentheses
-1y-6y-(-4(y-4))+18=0
We calculate terms in parentheses: -(-4(y-4)), so:
-4(y-4)
We multiply parentheses
-4y+16
Back to the equation:
-(-4y+16)
We add all the numbers together, and all the variables
-7y-(-4y+16)+18=0
We get rid of parentheses
-7y+4y-16+18=0
We add all the numbers together, and all the variables
-3y+2=0
We move all terms containing y to the left, all other terms to the right
-3y=-2
y=-2/-3
y=2/3

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