-2(3z+8)=1/3(9-18z)

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Solution for -2(3z+8)=1/3(9-18z) equation: 



-2(3z+8)=1/3(9-18z)

We move all terms to the left:

-2(3z+8)-(1/3(9-18z))=0



Domain of the equation: 3(9-18z))!=0

z∈R



We add all the numbers together, and all the variables

-2(3z+8)-(1/3(-18z+9))=0

We multiply parentheses

-6z-(1/3(-18z+9))-16=0

We multiply all the terms by the denominator


-6z*3(-18z+9))-(1-16*3(-18z+9))=0

Wy multiply elements

-18z^2(--48z(-=0

We use the square of the difference formula

-18z^2(+48z(-=0

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