-2(4+b)+2=12-(2+2b)

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Solution for -2(4+b)+2=12-(2+2b) equation: 



-2(4+b)+2=12-(2+2b)

We move all terms to the left:

-2(4+b)+2-(12-(2+2b))=0

We add all the numbers together, and all the variables

-2(b+4)-(12-(2b+2))+2=0

We multiply parentheses

-2b-(12-(2b+2))-8+2=0



We calculate terms in parentheses: -(12-(2b+2)), so:

12-(2b+2)

determiningTheFunctionDomain
-(2b+2)+12

We get rid of parentheses

-2b-2+12

We add all the numbers together, and all the variables

-2b+10

Back to the equation:

-(-2b+10)



We add all the numbers together, and all the variables

-2b-(-2b+10)-6=0

We get rid of parentheses

-2b+2b-10-6=0

We add all the numbers together, and all the variables

-16!=0

There is no solution for this equation

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