-2(4-2y)=y-6+3y-2

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Solution for -2(4-2y)=y-6+3y-2 equation: 



-2(4-2y)=y-6+3y-2

We move all terms to the left:

-2(4-2y)-(y-6+3y-2)=0

We add all the numbers together, and all the variables

-2(-2y+4)-(4y-8)=0

We multiply parentheses

4y-(4y-8)-8=0

We get rid of parentheses

4y-4y+8-8=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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