-2(4-x)+3x+2=-2x+4(x-1)-5

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Solution for -2(4-x)+3x+2=-2x+4(x-1)-5 equation: 



-2(4-x)+3x+2=-2x+4(x-1)-5

We move all terms to the left:

-2(4-x)+3x+2-(-2x+4(x-1)-5)=0

We add all the numbers together, and all the variables

-2(-1x+4)+3x-(-2x+4(x-1)-5)+2=0

We add all the numbers together, and all the variables

3x-2(-1x+4)-(-2x+4(x-1)-5)+2=0

We multiply parentheses

3x+2x-(-2x+4(x-1)-5)-8+2=0



We calculate terms in parentheses: -(-2x+4(x-1)-5), so:

-2x+4(x-1)-5

We multiply parentheses

-2x+4x-4-5

We add all the numbers together, and all the variables

2x-9

Back to the equation:

-(2x-9)



We add all the numbers together, and all the variables

5x-(2x-9)-6=0

We get rid of parentheses

5x-2x+9-6=0

We add all the numbers together, and all the variables

3x+3=0

We move all terms containing x to the left, all other terms to the right

3x=-3

x=-3/3

x=-1

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