-2(4-x)=6(x+2)+3x=

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Solution for -2(4-x)=6(x+2)+3x= equation: 



-2(4-x)=6(x+2)+3x=

We move all terms to the left:

-2(4-x)-(6(x+2)+3x)=0

We add all the numbers together, and all the variables

-2(-1x+4)-(6(x+2)+3x)=0

We multiply parentheses

2x-(6(x+2)+3x)-8=0



We calculate terms in parentheses: -(6(x+2)+3x), so:

6(x+2)+3x

We add all the numbers together, and all the variables

3x+6(x+2)

We multiply parentheses

3x+6x+12

We add all the numbers together, and all the variables

9x+12

Back to the equation:

-(9x+12)



We get rid of parentheses

2x-9x-12-8=0

We add all the numbers together, and all the variables

-7x-20=0

We move all terms containing x to the left, all other terms to the right

-7x=20

x=20/-7

x=-2+6/7

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