-2(4a-11)=5a-(3a-2)+10

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Solution for -2(4a-11)=5a-(3a-2)+10 equation: 



-2(4a-11)=5a-(3a-2)+10

We move all terms to the left:

-2(4a-11)-(5a-(3a-2)+10)=0

We multiply parentheses

-8a-(5a-(3a-2)+10)+22=0



We calculate terms in parentheses: -(5a-(3a-2)+10), so:

5a-(3a-2)+10

We get rid of parentheses

5a-3a+2+10

We add all the numbers together, and all the variables

2a+12

Back to the equation:

-(2a+12)



We get rid of parentheses

-8a-2a-12+22=0

We add all the numbers together, and all the variables

-10a+10=0

We move all terms containing a to the left, all other terms to the right

-10a=-10

a=-10/-10

a=1

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