-2(4t-1)+5(4-6t)=4t-2(t-1)

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Solution for -2(4t-1)+5(4-6t)=4t-2(t-1) equation: 



-2(4t-1)+5(4-6t)=4t-2(t-1)

We move all terms to the left:

-2(4t-1)+5(4-6t)-(4t-2(t-1))=0

We add all the numbers together, and all the variables

-2(4t-1)+5(-6t+4)-(4t-2(t-1))=0

We multiply parentheses

-8t-30t-(4t-2(t-1))+2+20=0



We calculate terms in parentheses: -(4t-2(t-1)), so:

4t-2(t-1)

We multiply parentheses

4t-2t+2

We add all the numbers together, and all the variables

2t+2

Back to the equation:

-(2t+2)



We add all the numbers together, and all the variables

-38t-(2t+2)+22=0

We get rid of parentheses

-38t-2t-2+22=0

We add all the numbers together, and all the variables

-40t+20=0

We move all terms containing t to the left, all other terms to the right

-40t=-20

t=-20/-40

t=1/2

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