-2(4t-2)+6t=8t-3

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Solution for -2(4t-2)+6t=8t-3 equation: 



-2(4t-2)+6t=8t-3

We move all terms to the left:

-2(4t-2)+6t-(8t-3)=0

We add all the numbers together, and all the variables

6t-2(4t-2)-(8t-3)=0

We multiply parentheses

6t-8t-(8t-3)+4=0

We get rid of parentheses

6t-8t-8t+3+4=0

We add all the numbers together, and all the variables

-10t+7=0

We move all terms containing t to the left, all other terms to the right

-10t=-7

t=-7/-10

t=7/10

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