-2(4u-3)+8u=6+4(4u-1)

Solution for -2(4u-3)+8u=6+4(4u-1) equation:

-2(4u-3)+8u=6+4(4u-1)

We move all terms to the left:

-2(4u-3)+8u-(6+4(4u-1))=0

We add all the numbers together, and all the variables

8u-2(4u-3)-(6+4(4u-1))=0

We multiply parentheses

8u-8u-(6+4(4u-1))+6=0


We calculate terms in parentheses: -(6+4(4u-1)), so:

6+4(4u-1)

determiningTheFunctionDomain
4(4u-1)+6

We multiply parentheses

16u-4+6

We add all the numbers together, and all the variables

16u+2

Back to the equation:

-(16u+2)


We add all the numbers together, and all the variables

-(16u+2)+6=0

We get rid of parentheses

-16u-2+6=0

We add all the numbers together, and all the variables

-16u+4=0

We move all terms containing u to the left, all other terms to the right

-16u=-4

u=-4/-16

u=1/4