-2(4u-4)+8u=8+3(4u-5)

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Solution for -2(4u-4)+8u=8+3(4u-5) equation: 



-2(4u-4)+8u=8+3(4u-5)

We move all terms to the left:

-2(4u-4)+8u-(8+3(4u-5))=0

We add all the numbers together, and all the variables

8u-2(4u-4)-(8+3(4u-5))=0

We multiply parentheses

8u-8u-(8+3(4u-5))+8=0



We calculate terms in parentheses: -(8+3(4u-5)), so:

8+3(4u-5)

determiningTheFunctionDomain
3(4u-5)+8

We multiply parentheses

12u-15+8

We add all the numbers together, and all the variables

12u-7

Back to the equation:

-(12u-7)



We add all the numbers together, and all the variables

-(12u-7)+8=0

We get rid of parentheses

-12u+7+8=0

We add all the numbers together, and all the variables

-12u+15=0

We move all terms containing u to the left, all other terms to the right

-12u=-15

u=-15/-12

u=1+1/4

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