-2(4u-6)+4u=6+4(3u-1)

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Solution for -2(4u-6)+4u=6+4(3u-1) equation: 



-2(4u-6)+4u=6+4(3u-1)

We move all terms to the left:

-2(4u-6)+4u-(6+4(3u-1))=0

We add all the numbers together, and all the variables

4u-2(4u-6)-(6+4(3u-1))=0

We multiply parentheses

4u-8u-(6+4(3u-1))+12=0



We calculate terms in parentheses: -(6+4(3u-1)), so:

6+4(3u-1)

determiningTheFunctionDomain
4(3u-1)+6

We multiply parentheses

12u-4+6

We add all the numbers together, and all the variables

12u+2

Back to the equation:

-(12u+2)



We add all the numbers together, and all the variables

-4u-(12u+2)+12=0

We get rid of parentheses

-4u-12u-2+12=0

We add all the numbers together, and all the variables

-16u+10=0

We move all terms containing u to the left, all other terms to the right

-16u=-10

u=-10/-16

u=5/8

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