-2(4u-8)+8u=6+2(4u-1)

Solution for -2(4u-8)+8u=6+2(4u-1) equation:

-2(4u-8)+8u=6+2(4u-1)

We move all terms to the left:

-2(4u-8)+8u-(6+2(4u-1))=0

We add all the numbers together, and all the variables

8u-2(4u-8)-(6+2(4u-1))=0

We multiply parentheses

8u-8u-(6+2(4u-1))+16=0


We calculate terms in parentheses: -(6+2(4u-1)), so:

6+2(4u-1)

determiningTheFunctionDomain
2(4u-1)+6

We multiply parentheses

8u-2+6

We add all the numbers together, and all the variables

8u+4

Back to the equation:

-(8u+4)


We add all the numbers together, and all the variables

-(8u+4)+16=0

We get rid of parentheses

-8u-4+16=0

We add all the numbers together, and all the variables

-8u+12=0

We move all terms containing u to the left, all other terms to the right

-8u=-12

u=-12/-8

u=1+1/2