-2(4v-2)+9v=2+5(3v-1)

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Solution for -2(4v-2)+9v=2+5(3v-1) equation: 



-2(4v-2)+9v=2+5(3v-1)

We move all terms to the left:

-2(4v-2)+9v-(2+5(3v-1))=0

We add all the numbers together, and all the variables

9v-2(4v-2)-(2+5(3v-1))=0

We multiply parentheses

9v-8v-(2+5(3v-1))+4=0



We calculate terms in parentheses: -(2+5(3v-1)), so:

2+5(3v-1)

determiningTheFunctionDomain
5(3v-1)+2

We multiply parentheses

15v-5+2

We add all the numbers together, and all the variables

15v-3

Back to the equation:

-(15v-3)



We add all the numbers together, and all the variables

v-(15v-3)+4=0

We get rid of parentheses

v-15v+3+4=0

We add all the numbers together, and all the variables

-14v+7=0

We move all terms containing v to the left, all other terms to the right

-14v=-7

v=-7/-14

v=1/2

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