-2(4w-2)+w=9+3(3w-5)

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Solution for -2(4w-2)+w=9+3(3w-5) equation: 



-2(4w-2)+w=9+3(3w-5)

We move all terms to the left:

-2(4w-2)+w-(9+3(3w-5))=0

We add all the numbers together, and all the variables

w-2(4w-2)-(9+3(3w-5))=0

We multiply parentheses

w-8w-(9+3(3w-5))+4=0



We calculate terms in parentheses: -(9+3(3w-5)), so:

9+3(3w-5)

determiningTheFunctionDomain
3(3w-5)+9

We multiply parentheses

9w-15+9

We add all the numbers together, and all the variables

9w-6

Back to the equation:

-(9w-6)



We add all the numbers together, and all the variables

-7w-(9w-6)+4=0

We get rid of parentheses

-7w-9w+6+4=0

We add all the numbers together, and all the variables

-16w+10=0

We move all terms containing w to the left, all other terms to the right

-16w=-10

w=-10/-16

w=5/8

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