-2(4x-3)+8x=6+3(3x-1)

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Solution for -2(4x-3)+8x=6+3(3x-1) equation: 



-2(4x-3)+8x=6+3(3x-1)

We move all terms to the left:

-2(4x-3)+8x-(6+3(3x-1))=0

We add all the numbers together, and all the variables

8x-2(4x-3)-(6+3(3x-1))=0

We multiply parentheses

8x-8x-(6+3(3x-1))+6=0



We calculate terms in parentheses: -(6+3(3x-1)), so:

6+3(3x-1)

determiningTheFunctionDomain
3(3x-1)+6

We multiply parentheses

9x-3+6

We add all the numbers together, and all the variables

9x+3

Back to the equation:

-(9x+3)



We add all the numbers together, and all the variables

-(9x+3)+6=0

We get rid of parentheses

-9x-3+6=0

We add all the numbers together, and all the variables

-9x+3=0

We move all terms containing x to the left, all other terms to the right

-9x=-3

x=-3/-9

x=1/3

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