-2(4x-4)=3(4-2/3x)

Solution for -2(4x-4)=3(4-2/3x) equation:

-2(4x-4)=3(4-2/3x)

We move all terms to the left:

-2(4x-4)-(3(4-2/3x))=0


Domain of the equation: 3x))!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-2(4x-4)-(3(-2/3x+4))=0

We multiply parentheses

-8x-(3(-2/3x+4))+8=0

We multiply all the terms by the denominator


-8x*3x+8*3x-2+4))-(3(+4))=0

We add all the numbers together, and all the variables

-8x*3x+8*3x-2+4))-(34)=0

We add all the numbers together, and all the variables

-8x*3x+8*3x=0

Wy multiply elements

-24x^2+24x=0

a = -24; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·(-24)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*-24}=\frac{-48}{-48}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*-24}=\frac{0}{-48}
=0
$