-2(4x-8)+6x=4+3(x-12)

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Solution for -2(4x-8)+6x=4+3(x-12) equation: 



-2(4x-8)+6x=4+3(x-12)

We move all terms to the left:

-2(4x-8)+6x-(4+3(x-12))=0

We add all the numbers together, and all the variables

6x-2(4x-8)-(4+3(x-12))=0

We multiply parentheses

6x-8x-(4+3(x-12))+16=0



We calculate terms in parentheses: -(4+3(x-12)), so:

4+3(x-12)

determiningTheFunctionDomain
3(x-12)+4

We multiply parentheses

3x-36+4

We add all the numbers together, and all the variables

3x-32

Back to the equation:

-(3x-32)



We add all the numbers together, and all the variables

-2x-(3x-32)+16=0

We get rid of parentheses

-2x-3x+32+16=0

We add all the numbers together, and all the variables

-5x+48=0

We move all terms containing x to the left, all other terms to the right

-5x=-48

x=-48/-5

x=9+3/5

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