-2(4y+8)=2(2y-3)+3y

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Solution for -2(4y+8)=2(2y-3)+3y equation: 



-2(4y+8)=2(2y-3)+3y

We move all terms to the left:

-2(4y+8)-(2(2y-3)+3y)=0

We multiply parentheses

-8y-(2(2y-3)+3y)-16=0



We calculate terms in parentheses: -(2(2y-3)+3y), so:

2(2y-3)+3y

We add all the numbers together, and all the variables

3y+2(2y-3)

We multiply parentheses

3y+4y-6

We add all the numbers together, and all the variables

7y-6

Back to the equation:

-(7y-6)



We get rid of parentheses

-8y-7y+6-16=0

We add all the numbers together, and all the variables

-15y-10=0

We move all terms containing y to the left, all other terms to the right

-15y=10

y=10/-15

y=-2/3

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