-2(4y-2)+4y=1+3(2y-1)

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Solution for -2(4y-2)+4y=1+3(2y-1) equation: 



-2(4y-2)+4y=1+3(2y-1)

We move all terms to the left:

-2(4y-2)+4y-(1+3(2y-1))=0

We add all the numbers together, and all the variables

4y-2(4y-2)-(1+3(2y-1))=0

We multiply parentheses

4y-8y-(1+3(2y-1))+4=0



We calculate terms in parentheses: -(1+3(2y-1)), so:

1+3(2y-1)

determiningTheFunctionDomain
3(2y-1)+1

We multiply parentheses

6y-3+1

We add all the numbers together, and all the variables

6y-2

Back to the equation:

-(6y-2)



We add all the numbers together, and all the variables

-4y-(6y-2)+4=0

We get rid of parentheses

-4y-6y+2+4=0

We add all the numbers together, and all the variables

-10y+6=0

We move all terms containing y to the left, all other terms to the right

-10y=-6

y=-6/-10

y=3/5

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