-2(4y-3)=3-(8y+2)

Solution for -2(4y-3)=3-(8y+2) equation:

Simplifying
-2(4y + -3) = 3 + -1(8y + 2)

Reorder the terms:
-2(-3 + 4y) = 3 + -1(8y + 2)
(-3 * -2 + 4y * -2) = 3 + -1(8y + 2)
(6 + -8y) = 3 + -1(8y + 2)

Reorder the terms:
6 + -8y = 3 + -1(2 + 8y)
6 + -8y = 3 + (2 * -1 + 8y * -1)
6 + -8y = 3 + (-2 + -8y)

Combine like terms: 3 + -2 = 1
6 + -8y = 1 + -8y

Add '8y' to each side of the equation.
6 + -8y + 8y = 1 + -8y + 8y

Combine like terms: -8y + 8y = 0
6 + 0 = 1 + -8y + 8y
6 = 1 + -8y + 8y

Combine like terms: -8y + 8y = 0
6 = 1 + 0
6 = 1

Solving
6 = 1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.