-2(4y-4)-y=-4(y-2)

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Solution for -2(4y-4)-y=-4(y-2) equation: 



-2(4y-4)-y=-4(y-2)

We move all terms to the left:

-2(4y-4)-y-(-4(y-2))=0

We add all the numbers together, and all the variables

-1y-2(4y-4)-(-4(y-2))=0

We multiply parentheses

-1y-8y-(-4(y-2))+8=0



We calculate terms in parentheses: -(-4(y-2)), so:

-4(y-2)

We multiply parentheses

-4y+8

Back to the equation:

-(-4y+8)



We add all the numbers together, and all the variables

-9y-(-4y+8)+8=0

We get rid of parentheses

-9y+4y-8+8=0

We add all the numbers together, and all the variables

-5y=0

y=0/-5

y=0

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