-2(5+4a)+3a=3-(2a+1)

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Solution for -2(5+4a)+3a=3-(2a+1) equation: 



-2(5+4a)+3a=3-(2a+1)

We move all terms to the left:

-2(5+4a)+3a-(3-(2a+1))=0

We add all the numbers together, and all the variables

-2(4a+5)+3a-(3-(2a+1))=0

We add all the numbers together, and all the variables

3a-2(4a+5)-(3-(2a+1))=0

We multiply parentheses

3a-8a-(3-(2a+1))-10=0



We calculate terms in parentheses: -(3-(2a+1)), so:

3-(2a+1)

determiningTheFunctionDomain
-(2a+1)+3

We get rid of parentheses

-2a-1+3

We add all the numbers together, and all the variables

-2a+2

Back to the equation:

-(-2a+2)



We add all the numbers together, and all the variables

-5a-(-2a+2)-10=0

We get rid of parentheses

-5a+2a-2-10=0

We add all the numbers together, and all the variables

-3a-12=0

We move all terms containing a to the left, all other terms to the right

-3a=12

a=12/-3

a=-4

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