-2(5+z)-20=50+6z

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Solution for -2(5+z)-20=50+6z equation: 



-2(5+z)-20=50+6z

We move all terms to the left:

-2(5+z)-20-(50+6z)=0

We add all the numbers together, and all the variables

-2(z+5)-(6z+50)-20=0

We multiply parentheses

-2z-(6z+50)-10-20=0

We get rid of parentheses

-2z-6z-50-10-20=0

We add all the numbers together, and all the variables

-8z-80=0

We move all terms containing z to the left, all other terms to the right

-8z=80

z=80/-8

z=-10

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