-2(5b-4)=32-2b

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Solution for -2(5b-4)=32-2b equation: 



-2(5b-4)=32-2b

We move all terms to the left:

-2(5b-4)-(32-2b)=0

We add all the numbers together, and all the variables

-2(5b-4)-(-2b+32)=0

We multiply parentheses

-10b-(-2b+32)+8=0

We get rid of parentheses

-10b+2b-32+8=0

We add all the numbers together, and all the variables

-8b-24=0

We move all terms containing b to the left, all other terms to the right

-8b=24

b=24/-8

b=-3

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