-2(5v-4)+7v=2+3(2v-3)

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Solution for -2(5v-4)+7v=2+3(2v-3) equation:



-2(5v-4)+7v=2+3(2v-3)
We move all terms to the left:
-2(5v-4)+7v-(2+3(2v-3))=0
We add all the numbers together, and all the variables
7v-2(5v-4)-(2+3(2v-3))=0
We multiply parentheses
7v-10v-(2+3(2v-3))+8=0
We calculate terms in parentheses: -(2+3(2v-3)), so:
2+3(2v-3)
determiningTheFunctionDomain 3(2v-3)+2
We multiply parentheses
6v-9+2
We add all the numbers together, and all the variables
6v-7
Back to the equation:
-(6v-7)
We add all the numbers together, and all the variables
-3v-(6v-7)+8=0
We get rid of parentheses
-3v-6v+7+8=0
We add all the numbers together, and all the variables
-9v+15=0
We move all terms containing v to the left, all other terms to the right
-9v=-15
v=-15/-9
v=1+2/3

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