-2(5v-4)+7v=2+3(2v-3)

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Solution for -2(5v-4)+7v=2+3(2v-3) equation: 



-2(5v-4)+7v=2+3(2v-3)

We move all terms to the left:

-2(5v-4)+7v-(2+3(2v-3))=0

We add all the numbers together, and all the variables

7v-2(5v-4)-(2+3(2v-3))=0

We multiply parentheses

7v-10v-(2+3(2v-3))+8=0



We calculate terms in parentheses: -(2+3(2v-3)), so:

2+3(2v-3)

determiningTheFunctionDomain
3(2v-3)+2

We multiply parentheses

6v-9+2

We add all the numbers together, and all the variables

6v-7

Back to the equation:

-(6v-7)



We add all the numbers together, and all the variables

-3v-(6v-7)+8=0

We get rid of parentheses

-3v-6v+7+8=0

We add all the numbers together, and all the variables

-9v+15=0

We move all terms containing v to the left, all other terms to the right

-9v=-15

v=-15/-9

v=1+2/3

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