-2(5x-1)=-4x(x+5)

Solution for -2(5x-1)=-4x(x+5) equation:

-2(5x-1)=-4x(x+5)

We move all terms to the left:

-2(5x-1)-(-4x(x+5))=0

We multiply parentheses

-10x-(-4x(x+5))+2=0


We calculate terms in parentheses: -(-4x(x+5)), so:

-4x(x+5)

We multiply parentheses

-4x^2-20x

Back to the equation:

-(-4x^2-20x)


We get rid of parentheses

4x^2+20x-10x+2=0

We add all the numbers together, and all the variables

4x^2+10x+2=0

a = 4; b = 10; c = +2;
Δ = b2-4ac
Δ = 102-4·4·2
Δ = 68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{68}=\sqrt{4*17}=\sqrt{4}*\sqrt{17}=2\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{17}}{2*4}=\frac{-10-2\sqrt{17}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{17}}{2*4}=\frac{-10+2\sqrt{17}}{8}
$