-2(5y-4)-y=3(y-2)

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Solution for -2(5y-4)-y=3(y-2) equation: 



-2(5y-4)-y=3(y-2)

We move all terms to the left:

-2(5y-4)-y-(3(y-2))=0

We add all the numbers together, and all the variables

-1y-2(5y-4)-(3(y-2))=0

We multiply parentheses

-1y-10y-(3(y-2))+8=0



We calculate terms in parentheses: -(3(y-2)), so:

3(y-2)

We multiply parentheses

3y-6

Back to the equation:

-(3y-6)



We add all the numbers together, and all the variables

-11y-(3y-6)+8=0

We get rid of parentheses

-11y-3y+6+8=0

We add all the numbers together, and all the variables

-14y+14=0

We move all terms containing y to the left, all other terms to the right

-14y=-14

y=-14/-14

y=1

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