-2(6+4b)=-8b-2(b-5)

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Solution for -2(6+4b)=-8b-2(b-5) equation: 



-2(6+4b)=-8b-2(b-5)

We move all terms to the left:

-2(6+4b)-(-8b-2(b-5))=0

We add all the numbers together, and all the variables

-2(4b+6)-(-8b-2(b-5))=0

We multiply parentheses

-8b-(-8b-2(b-5))-12=0



We calculate terms in parentheses: -(-8b-2(b-5)), so:

-8b-2(b-5)

We multiply parentheses

-8b-2b+10

We add all the numbers together, and all the variables

-10b+10

Back to the equation:

-(-10b+10)



We get rid of parentheses

-8b+10b-10-12=0

We add all the numbers together, and all the variables

2b-22=0

We move all terms containing b to the left, all other terms to the right

2b=22

b=22/2

b=11

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