-2(6-2n)=4(n-3)

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Solution for -2(6-2n)=4(n-3) equation: 



-2(6-2n)=4(n-3)

We move all terms to the left:

-2(6-2n)-(4(n-3))=0

We add all the numbers together, and all the variables

-2(-2n+6)-(4(n-3))=0

We multiply parentheses

4n-(4(n-3))-12=0



We calculate terms in parentheses: -(4(n-3)), so:

4(n-3)

We multiply parentheses

4n-12

Back to the equation:

-(4n-12)



We get rid of parentheses

4n-4n+12-12=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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