-2(6-b)=10+2(b-12)

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Solution for -2(6-b)=10+2(b-12) equation: 



-2(6-b)=10+2(b-12)

We move all terms to the left:

-2(6-b)-(10+2(b-12))=0

We add all the numbers together, and all the variables

-2(-1b+6)-(10+2(b-12))=0

We multiply parentheses

2b-(10+2(b-12))-12=0



We calculate terms in parentheses: -(10+2(b-12)), so:

10+2(b-12)

determiningTheFunctionDomain
2(b-12)+10

We multiply parentheses

2b-24+10

We add all the numbers together, and all the variables

2b-14

Back to the equation:

-(2b-14)



We get rid of parentheses

2b-2b+14-12=0

We add all the numbers together, and all the variables

2!=0

There is no solution for this equation

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