-2(6u-1)+8u=2(u+2)

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Solution for -2(6u-1)+8u=2(u+2) equation: 



-2(6u-1)+8u=2(u+2)

We move all terms to the left:

-2(6u-1)+8u-(2(u+2))=0

We add all the numbers together, and all the variables

8u-2(6u-1)-(2(u+2))=0

We multiply parentheses

8u-12u-(2(u+2))+2=0



We calculate terms in parentheses: -(2(u+2)), so:

2(u+2)

We multiply parentheses

2u+4

Back to the equation:

-(2u+4)



We add all the numbers together, and all the variables

-4u-(2u+4)+2=0

We get rid of parentheses

-4u-2u-4+2=0

We add all the numbers together, and all the variables

-6u-2=0

We move all terms containing u to the left, all other terms to the right

-6u=2

u=2/-6

u=-1/3

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