-2(6u-3)+3u=3(u+4)

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Solution for -2(6u-3)+3u=3(u+4) equation:



-2(6u-3)+3u=3(u+4)
We move all terms to the left:
-2(6u-3)+3u-(3(u+4))=0
We add all the numbers together, and all the variables
3u-2(6u-3)-(3(u+4))=0
We multiply parentheses
3u-12u-(3(u+4))+6=0
We calculate terms in parentheses: -(3(u+4)), so:
3(u+4)
We multiply parentheses
3u+12
Back to the equation:
-(3u+12)
We add all the numbers together, and all the variables
-9u-(3u+12)+6=0
We get rid of parentheses
-9u-3u-12+6=0
We add all the numbers together, and all the variables
-12u-6=0
We move all terms containing u to the left, all other terms to the right
-12u=6
u=6/-12
u=-1/2

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