-2(6u-4)+4u=2(u+8)

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Solution for -2(6u-4)+4u=2(u+8) equation:



-2(6u-4)+4u=2(u+8)
We move all terms to the left:
-2(6u-4)+4u-(2(u+8))=0
We add all the numbers together, and all the variables
4u-2(6u-4)-(2(u+8))=0
We multiply parentheses
4u-12u-(2(u+8))+8=0
We calculate terms in parentheses: -(2(u+8)), so:
2(u+8)
We multiply parentheses
2u+16
Back to the equation:
-(2u+16)
We add all the numbers together, and all the variables
-8u-(2u+16)+8=0
We get rid of parentheses
-8u-2u-16+8=0
We add all the numbers together, and all the variables
-10u-8=0
We move all terms containing u to the left, all other terms to the right
-10u=8
u=8/-10
u=-4/5

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