-2(6v-4)+4v=2(v+6)

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Solution for -2(6v-4)+4v=2(v+6) equation: 



-2(6v-4)+4v=2(v+6)

We move all terms to the left:

-2(6v-4)+4v-(2(v+6))=0

We add all the numbers together, and all the variables

4v-2(6v-4)-(2(v+6))=0

We multiply parentheses

4v-12v-(2(v+6))+8=0



We calculate terms in parentheses: -(2(v+6)), so:

2(v+6)

We multiply parentheses

2v+12

Back to the equation:

-(2v+12)



We add all the numbers together, and all the variables

-8v-(2v+12)+8=0

We get rid of parentheses

-8v-2v-12+8=0

We add all the numbers together, and all the variables

-10v-4=0

We move all terms containing v to the left, all other terms to the right

-10v=4

v=4/-10

v=-2/5

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