-2(6x+8)+7x=3x-2(12+4x)+8

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Solution for -2(6x+8)+7x=3x-2(12+4x)+8 equation: 



-2(6x+8)+7x=3x-2(12+4x)+8

We move all terms to the left:

-2(6x+8)+7x-(3x-2(12+4x)+8)=0

We add all the numbers together, and all the variables

-2(6x+8)+7x-(3x-2(4x+12)+8)=0

We add all the numbers together, and all the variables

7x-2(6x+8)-(3x-2(4x+12)+8)=0

We multiply parentheses

7x-12x-(3x-2(4x+12)+8)-16=0



We calculate terms in parentheses: -(3x-2(4x+12)+8), so:

3x-2(4x+12)+8

We multiply parentheses

3x-8x-24+8

We add all the numbers together, and all the variables

-5x-16

Back to the equation:

-(-5x-16)



We add all the numbers together, and all the variables

-5x-(-5x-16)-16=0

We get rid of parentheses

-5x+5x+16-16=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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