-2(6y-1)+3y=5(y+4)

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Solution for -2(6y-1)+3y=5(y+4) equation: 



-2(6y-1)+3y=5(y+4)

We move all terms to the left:

-2(6y-1)+3y-(5(y+4))=0

We add all the numbers together, and all the variables

3y-2(6y-1)-(5(y+4))=0

We multiply parentheses

3y-12y-(5(y+4))+2=0



We calculate terms in parentheses: -(5(y+4)), so:

5(y+4)

We multiply parentheses

5y+20

Back to the equation:

-(5y+20)



We add all the numbers together, and all the variables

-9y-(5y+20)+2=0

We get rid of parentheses

-9y-5y-20+2=0

We add all the numbers together, and all the variables

-14y-18=0

We move all terms containing y to the left, all other terms to the right

-14y=18

y=18/-14

y=-1+2/7

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