-2(6y-1)+5y=3(y+2)

Solution for -2(6y-1)+5y=3(y+2) equation:

-2(6y-1)+5y=3(y+2)

We move all terms to the left:

-2(6y-1)+5y-(3(y+2))=0

We add all the numbers together, and all the variables

5y-2(6y-1)-(3(y+2))=0

We multiply parentheses

5y-12y-(3(y+2))+2=0


We calculate terms in parentheses: -(3(y+2)), so:

3(y+2)

We multiply parentheses

3y+6

Back to the equation:

-(3y+6)


We add all the numbers together, and all the variables

-7y-(3y+6)+2=0

We get rid of parentheses

-7y-3y-6+2=0

We add all the numbers together, and all the variables

-10y-4=0

We move all terms containing y to the left, all other terms to the right

-10y=4

y=4/-10

y=-2/5