-2(6y-10)-y=-3(y-2)

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Solution for -2(6y-10)-y=-3(y-2) equation: 



-2(6y-10)-y=-3(y-2)

We move all terms to the left:

-2(6y-10)-y-(-3(y-2))=0

We add all the numbers together, and all the variables

-1y-2(6y-10)-(-3(y-2))=0

We multiply parentheses

-1y-12y-(-3(y-2))+20=0



We calculate terms in parentheses: -(-3(y-2)), so:

-3(y-2)

We multiply parentheses

-3y+6

Back to the equation:

-(-3y+6)



We add all the numbers together, and all the variables

-13y-(-3y+6)+20=0

We get rid of parentheses

-13y+3y-6+20=0

We add all the numbers together, and all the variables

-10y+14=0

We move all terms containing y to the left, all other terms to the right

-10y=-14

y=-14/-10

y=1+2/5

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