-2(6y-4)-y=-2(y-2)

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Solution for -2(6y-4)-y=-2(y-2) equation:



-2(6y-4)-y=-2(y-2)
We move all terms to the left:
-2(6y-4)-y-(-2(y-2))=0
We add all the numbers together, and all the variables
-1y-2(6y-4)-(-2(y-2))=0
We multiply parentheses
-1y-12y-(-2(y-2))+8=0
We calculate terms in parentheses: -(-2(y-2)), so:
-2(y-2)
We multiply parentheses
-2y+4
Back to the equation:
-(-2y+4)
We add all the numbers together, and all the variables
-13y-(-2y+4)+8=0
We get rid of parentheses
-13y+2y-4+8=0
We add all the numbers together, and all the variables
-11y+4=0
We move all terms containing y to the left, all other terms to the right
-11y=-4
y=-4/-11
y=4/11

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