-2(6y-7)+4y=2(y+3)

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Solution for -2(6y-7)+4y=2(y+3) equation: 



-2(6y-7)+4y=2(y+3)

We move all terms to the left:

-2(6y-7)+4y-(2(y+3))=0

We add all the numbers together, and all the variables

4y-2(6y-7)-(2(y+3))=0

We multiply parentheses

4y-12y-(2(y+3))+14=0



We calculate terms in parentheses: -(2(y+3)), so:

2(y+3)

We multiply parentheses

2y+6

Back to the equation:

-(2y+6)



We add all the numbers together, and all the variables

-8y-(2y+6)+14=0

We get rid of parentheses

-8y-2y-6+14=0

We add all the numbers together, and all the variables

-10y+8=0

We move all terms containing y to the left, all other terms to the right

-10y=-8

y=-8/-10

y=4/5

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