-2(7u-2)+2u=9+2(3u-1)

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Solution for -2(7u-2)+2u=9+2(3u-1) equation: 



-2(7u-2)+2u=9+2(3u-1)

We move all terms to the left:

-2(7u-2)+2u-(9+2(3u-1))=0

We add all the numbers together, and all the variables

2u-2(7u-2)-(9+2(3u-1))=0

We multiply parentheses

2u-14u-(9+2(3u-1))+4=0



We calculate terms in parentheses: -(9+2(3u-1)), so:

9+2(3u-1)

determiningTheFunctionDomain
2(3u-1)+9

We multiply parentheses

6u-2+9

We add all the numbers together, and all the variables

6u+7

Back to the equation:

-(6u+7)



We add all the numbers together, and all the variables

-12u-(6u+7)+4=0

We get rid of parentheses

-12u-6u-7+4=0

We add all the numbers together, and all the variables

-18u-3=0

We move all terms containing u to the left, all other terms to the right

-18u=3

u=3/-18

u=-1/6

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