-2(7u-8)+6u=4+2(4u-3)

Solution for -2(7u-8)+6u=4+2(4u-3) equation:

-2(7u-8)+6u=4+2(4u-3)

We move all terms to the left:

-2(7u-8)+6u-(4+2(4u-3))=0

We add all the numbers together, and all the variables

6u-2(7u-8)-(4+2(4u-3))=0

We multiply parentheses

6u-14u-(4+2(4u-3))+16=0


We calculate terms in parentheses: -(4+2(4u-3)), so:

4+2(4u-3)

determiningTheFunctionDomain
2(4u-3)+4

We multiply parentheses

8u-6+4

We add all the numbers together, and all the variables

8u-2

Back to the equation:

-(8u-2)


We add all the numbers together, and all the variables

-8u-(8u-2)+16=0

We get rid of parentheses

-8u-8u+2+16=0

We add all the numbers together, and all the variables

-16u+18=0

We move all terms containing u to the left, all other terms to the right

-16u=-18

u=-18/-16

u=1+1/8