-2(7y-6)+6y=4+2(2y-4)

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Solution for -2(7y-6)+6y=4+2(2y-4) equation: 



-2(7y-6)+6y=4+2(2y-4)

We move all terms to the left:

-2(7y-6)+6y-(4+2(2y-4))=0

We add all the numbers together, and all the variables

6y-2(7y-6)-(4+2(2y-4))=0

We multiply parentheses

6y-14y-(4+2(2y-4))+12=0



We calculate terms in parentheses: -(4+2(2y-4)), so:

4+2(2y-4)

determiningTheFunctionDomain
2(2y-4)+4

We multiply parentheses

4y-8+4

We add all the numbers together, and all the variables

4y-4

Back to the equation:

-(4y-4)



We add all the numbers together, and all the variables

-8y-(4y-4)+12=0

We get rid of parentheses

-8y-4y+4+12=0

We add all the numbers together, and all the variables

-12y+16=0

We move all terms containing y to the left, all other terms to the right

-12y=-16

y=-16/-12

y=1+1/3

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