-2(8u-3)+6u=2(u+8)

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Solution for -2(8u-3)+6u=2(u+8) equation: 



-2(8u-3)+6u=2(u+8)

We move all terms to the left:

-2(8u-3)+6u-(2(u+8))=0

We add all the numbers together, and all the variables

6u-2(8u-3)-(2(u+8))=0

We multiply parentheses

6u-16u-(2(u+8))+6=0



We calculate terms in parentheses: -(2(u+8)), so:

2(u+8)

We multiply parentheses

2u+16

Back to the equation:

-(2u+16)



We add all the numbers together, and all the variables

-10u-(2u+16)+6=0

We get rid of parentheses

-10u-2u-16+6=0

We add all the numbers together, and all the variables

-12u-10=0

We move all terms containing u to the left, all other terms to the right

-12u=10

u=10/-12

u=-5/6

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