-2(8u-5)+9u=5+3(u-1)

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Solution for -2(8u-5)+9u=5+3(u-1) equation: 



-2(8u-5)+9u=5+3(u-1)

We move all terms to the left:

-2(8u-5)+9u-(5+3(u-1))=0

We add all the numbers together, and all the variables

9u-2(8u-5)-(5+3(u-1))=0

We multiply parentheses

9u-16u-(5+3(u-1))+10=0



We calculate terms in parentheses: -(5+3(u-1)), so:

5+3(u-1)

determiningTheFunctionDomain
3(u-1)+5

We multiply parentheses

3u-3+5

We add all the numbers together, and all the variables

3u+2

Back to the equation:

-(3u+2)



We add all the numbers together, and all the variables

-7u-(3u+2)+10=0

We get rid of parentheses

-7u-3u-2+10=0

We add all the numbers together, and all the variables

-10u+8=0

We move all terms containing u to the left, all other terms to the right

-10u=-8

u=-8/-10

u=4/5

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